230=-16t^2+150t

Solution for 230=-16t^2+150t equation:

230=-16t^2+150t

We move all terms to the left:

230-(-16t^2+150t)=0

We get rid of parentheses

16t^2-150t+230=0

a = 16; b = -150; c = +230;
Δ = b2-4ac
Δ = -1502-4·16·230
Δ = 7780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7780}=\sqrt{4*1945}=\sqrt{4}*\sqrt{1945}=2\sqrt{1945}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{1945}}{2*16}=\frac{150-2\sqrt{1945}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{1945}}{2*16}=\frac{150+2\sqrt{1945}}{32}
$